I don't know how to do this the speed of train A is 18mph slower than the speed of train B train A travels 190 miles in the same time it takes train B to travel 280 miles find the speed of each train please help so i can pass my quiz.
speed of train B --- x mph
speed of train A --- x - 18 mph
for A: time to go 190 miles = 190/(x-18)
for B: time to go 280 miles = 280/x
but these two times are equal, so ....
190/(x-18) = 280/x
280x - 5040 = 190x
70x = 5040
x = 72
take it from there
To solve this problem, let's use the formula for speed:
Speed = Distance / Time
We know that the distance traveled by train A is 190 miles and the distance traveled by train B is 280 miles. Let's assign variables to the speeds of train A and train B.
Let's assume the speed of train B is "x" mph. According to the problem, the speed of train A is 18 mph slower than the speed of train B, so we can represent the speed of train A as "x - 18" mph.
Next, we need to find the time it takes for each train to travel their respective distances. Since time is equal for both trains, we can set up the following equation:
Time for train A = Time for train B
Distance for train A / Speed for train A = Distance for train B / Speed for train B
Now, let's substitute the given values:
190 / (x - 18) = 280 / x
To solve this equation, you can cross-multiply:
190x = 280(x - 18)
Now, simplify and solve for x:
190x = 280x - 5040
5040 = 90x
x = 5040 / 90
x = 56
So, the speed of train B is 56 mph.
To find the speed of train A, substitute the value of x in the equation:
Speed of train A = x - 18
Speed of train A = 56 - 18 = 38 mph
Therefore, the speed of train A is 38 mph and the speed of train B is 56 mph.