Chemistry

What quantity of heat is necessary to convert 50.0 g of ice at 0.0 C into steam 100,0 C? The heat of fusion is 80.0 cal/g, the heat of vaporization is 540 cal/g, and the specific heat of water is 1.00 cal/gC.

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  1. q1 = heat needed to melt ice at zero C to liquid water at zero C.
    q1 = mass ice x heat fusion

    q2 = heat needed to raise T from zero C to 100 C.
    q2 = mass melted ice x specific heat water x (Tfinal-Tinitial)

    q3 = heat needed to vaporize water at 100 to steam at 100.
    q3 = mass water x heat vaporization.

    Total Q = q1 + q2 + q3.

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