Physics

A small plastic ball with a mass of 6.50x10^-3 kg and with a charge of +0.150x10^-6 C is suspended from an insulating thread and hangs between the plates of a capacitor. The ball is in equilibrium, whit the tread making an angle of 30 degrees with respect to the vertical. The area of each plate is 0.0150 m^2. What is the magnitude of the charge of each plate?

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asked by Trevor
  1. Are the capacitor plates horizontal or vertical or aligned tih the thread? How is the thread prevented from interfering with the capacitor plates?

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    posted by drwls
  2. dr wls is here now so there is hope.

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    posted by Damon
  3. They Are Vertical with the ball in between them.

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    posted by Trevor
  4. Force down = m g = 6.5*10^-3 *9.8 = 53.7*10^-3 N
    Force sideways = q E
    where E = sigma/eo
    so force sideways = q sigma/eo
    then
    tan 30 = (q sigma /eo)/53.7*10^-3
    you know q, eo
    so solve for sigma
    charge = sigma * plate area

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    posted by Damon
  5. what does sigma represent?

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    posted by john

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