A capacitor is made from two 1.2 cm diameter coins separated by a 0.18 mm thick piece of paper (K = 3.7). A 6 V battery is connected to the capacitor. How much charge is on each coin?

My solution:
C= K * Permitivity * A/d = q/v

I solved for q and got 1.2 X 10^-10

But i still got it wrong. Can someone please check and see where i went wrong or check to see if you arrive at a different answer

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  1. Area = 1.131*10^-4 m^2
    d = 1.8*10^-4 m
    epsilon = 8.85*10^-12
    C = 2.06*10^-11 F
    q = CV = 1.2*10^-10 coulombs

    I agree with your answer

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