Consider the reaction.
PbCO3(s)<--> PbO(s) + CO2(g).

calculate the equilibrium pressure of CO2 in the system at the following temperatures.(IN atm)

(a) 270°C

(b) 480°C

..... delta Hf(KJ/mol).. d.Gf(KJ/mol).. S(J/mol-K)
PbCO3(s)..-699.1 .. -625.5 .. 131.0

PbO(s) .. -217.3 .. -187.9 .. 68.70

CO2(g) ... -393.5 .. -394.4 .. 213.6

Please help me!!! U could help me on the first one then i'll do the second one myself

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  1. I think you can calculate dGf for the reaction (n*dGf products)-n*dGo reactants) and from there dGo = -RTlnK. Solve for ln K at each T.
    Then lnK = pCO2

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  2. So do i plug in 270C in kelvin as my temp in the first formula???

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  3. yes

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  4. i still don't get the right answer
    i have like 1.54*10-14

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  5. What is the right answer? I calculated K and obtained 6.98E-5.

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