given; how many grams of fe2o3 can be converted to fe3o4 by 14 grams of co?
To determine how many grams of Fe2O3 can be converted to Fe3O4 by 14 grams of CO, we first need to set up a balanced chemical equation for the reaction between Fe2O3 and CO.
The balanced equation is:
3 Fe2O3 + CO -> 2 Fe3O4 + CO2
From the balanced equation, we can see that it takes 3 moles of Fe2O3 to react with 1 mole of CO to produce 2 moles of Fe3O4.
1 mole of CO has a molar mass of approximately 28 g/mol, so 14 grams of CO is equal to:
14 g CO / 28 g/mol = 0.5 moles of CO
Since the molar ratio between Fe2O3 and Fe3O4 is 3:2, we can calculate the moles of Fe2O3 reacted using the ratio:
0.5 moles of CO * (3 moles of Fe2O3 / 1 mole of CO) = 1.5 moles of Fe2O3
Now we need to convert the moles of Fe2O3 to grams. The molar mass of Fe2O3 is approximately 160 g/mol.
1.5 moles of Fe2O3 * 160 g/mol = 240 grams of Fe2O3
Therefore, 14 grams of CO can convert 240 grams of Fe2O3 to Fe3O4.