Using calories, how much heat will 32 grams of water absorb when it is heated from 25 C to 80 C?

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  1. q = heat absorbed = mass x specific heat water x (Tf - Ti) where
    mass = 32 grams.
    You will need to look up the specific heat of water. I think it's about 4 J/g*C.
    Tf is final temperature. Ti is initial T.
    Post your work if you get stuck.

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