
psst... use a calculater....lol

Becky, I will assume you meant
(7x+3)+(4x^2+1)/(2x10)
Use brackets to eliminate any ambiguity.
Your common denominator is 2x10, so
[(7x+3)(2x10) + (4x^2 + 1)]/(2x10)
= [14x^2+70x+6x30+4x^2+1]/(2x10)
= (10x^2 +76x  29)/(2x10)
strange question, I don't think "simplifying" this type of mess gains you anything, the result looks more complicated than the original question


No, really the problem is &7x+3)+(4^2+1/2 {one half}x10
I came up with
14x^2+8x^213 over 2 Is this correct?

in that case the question is quite simple, but there is really no need at all for the brackets, you would simply have
7x+3+4^2+1/2 x10
Using a common denominator of 2 would give
(14x + 6 + 8x^2 + x  20)/2
= (8x^2  13x  14)/2