algebra

(-7x+3)+(4x^2+1/2x-10)

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  1. psst... use a calculater....lol

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  2. Becky, I will assume you meant
    (-7x+3)+(4x^2+1)/(2x-10)

    Use brackets to eliminate any ambiguity.

    Your common denominator is 2x-10, so

    [(-7x+3)(2x-10) + (4x^2 + 1)]/(2x-10)
    = [-14x^2+70x+6x-30+4x^2+1]/(2x-10)
    = (-10x^2 +76x - 29)/(2x-10)

    strange question, I don't think "simplifying" this type of mess gains you anything, the result looks more complicated than the original question

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  3. No, really the problem is &-7x+3)+(4^2+1/2 {one half}x-10

    I came up with

    -14x^2+8x^2-13 over 2 Is this correct?

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  4. in that case the question is quite simple, but there is really no need at all for the brackets, you would simply have
    -7x+3+4^2+1/2 x-10

    Using a common denominator of 2 would give

    (-14x + 6 + 8x^2 + x - 20)/2
    = (8x^2 - 13x - 14)/2

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