2a+3b=9
3a+2b=12
what are you support to do.
If you are trying to solve for a and b,
multiply the first equation by 3 and the second equation by 2.
6a + 9b = 27
6a + 4b = 24
Now subtract them
5b = 3
b = 3/5
Now substitute thab b in the first equation
2a + 9/5 = 9
2a = 36/5
a = 18/5
To solve this system of equations, you can use the method of substitution:
Step 1: Solve one of the equations for one variable in terms of the other variable.
Let's solve the first equation for 'a':
2a + 3b = 9
2a = 9 - 3b
a = (9 - 3b) / 2
Step 2: Substitute the expression you found for 'a' into the other equation.
Replace 'a' in the second equation with the expression we obtained:
3((9 - 3b) / 2) + 2b = 12
Step 3: Simplify and solve for 'b'.
Expand the equation and solve for 'b':
(27 - 9b) / 2 + 2b = 12
(27 - 9b + 4b) / 2 = 12
(27 - 5b) / 2 = 12
27 - 5b = 24
-5b = -3
b = 3/5
Step 4: Substitute the value of 'b' back into one of the original equations to solve for 'a'.
Let's substitute 'b = 3/5' into the first equation:
2a + 3(3/5) = 9
2a + 9/5 = 9
2a = 9 - 9/5
2a = 36/5 - 9/5
2a = 27/5
a = (27/5) / 2
a = 27/10
Therefore, the solution to the system of equations is:
a = 27/10
b = 3/5