how many 8' tiles are needed to tile a 8' by 18' floor? how much money will it cost if tiles are $2.75 each?
(8x18 ft^2)/[(2/3)^2 ft^2/tile]*2.75 $/tile) = _______ $
have 35sqft to cover using 8"tiles how many needed to do the job?
To find out how many 8' tiles are needed to tile a 8' by 18' floor, we can divide the total area of the floor by the area of each tile.
First, let's calculate the area of the floor:
Area of the floor = length × width
= 8' × 18'
= 144 square feet
Next, we need to calculate the area of each tile:
Area of each tile = length × width
= 8' × 8'
= 64 square feet
To find the number of tiles needed, we divide the area of the floor by the area of each tile:
Number of tiles needed = Area of the floor ÷ Area of each tile
= 144 square feet ÷ 64 square feet
≈ 2.25 tiles
Since we can't use a fraction of a tile, we need to round up to the nearest whole number. Therefore, we would need at least 3 tiles.
To calculate the cost, we multiply the number of tiles needed by the cost per tile:
Cost = Number of tiles × Cost per tile
= 3 tiles × $2.75 per tile
= $8.25
So, the cost to tile the floor with 8' tiles would be $8.25.