A rocket carrying a satellite is accelerating straight up from the earth's surface. At 1.20 after liftoff, the rocket clears the top of its launch platform, 68 above the ground. After an additional 4.85 , it is 1.50 above the ground.Calculate the magnitude of the average velocity of the rocket for the 4.85 part of its flight. Calculate the magnitude of the average velocity of the rocket the first 6.05 of its flight.
To calculate the average velocity, we need to divide the total displacement by the total time taken.
For the 4.85 second part of its flight:
- Initial height (h1) = 68 m
- Final height (h2) = 1.50 m
- Time taken (t) = 4.85 s
Displacement (d) = final height - initial height
d = h2 - h1
d = 1.50 m - 68 m
d = -66.5 m (negative sign indicates direction opposite to upward)
Average velocity (v) = displacement / time taken
v = d / t
v = (-66.5 m) / (4.85 s) = -13.7 m/s
Therefore, the magnitude of the average velocity for the 4.85 second part of its flight is 13.7 m/s.
For the first 6.05 second part of its flight:
- Initial height (h1) = 68 m
- Final height (h2) = 1.50 m
- Time taken (t) = 6.05 s
Displacement (d) = final height - initial height
d = h2 - h1
d = 1.50 m - 68 m
d = -66.5 m (negative sign indicates direction opposite to upward)
Average velocity (v) = displacement / time taken
v = d / t
v = (-66.5 m) / (6.05 s) = -10.98 m/s
Therefore, the magnitude of the average velocity for the first 6.05 seconds of its flight is 10.98 m/s.
To calculate the average velocity of an object, you need to divide the total displacement of the object by the total time it took to cover that displacement.
For the first 6.05 seconds of the rocket's flight, we need to find its average velocity. The rocket starts at ground level (0 meters) and reaches a height of 68 meters after 1.20 seconds. This means the displacement in the first 1.20 seconds is 68 meters.
After an additional 4.85 seconds (totaling 6.05 seconds), the rocket is at a height of 1.50 meters above the ground. The displacement in this entire duration is from 68 meters above the ground to 1.50 meters above the ground. So, the total displacement in the first 6.05 seconds is 68 - 1.50 = 66.50 meters.
Now, we can calculate the average velocity by dividing the total displacement by the total time:
Average velocity = total displacement / total time
Average velocity = 66.50 meters / 6.05 seconds
Average velocity ≈ 10.99 m/s
Therefore, the magnitude of the average velocity of the rocket for the 6.05 seconds of its flight is approximately 10.99 m/s.
For the 4.85 seconds part of the flight, the rocket starts at a height of 68 meters above the ground and ends at a height of 1.5 meters above the ground. The total displacement for this duration is 68 - 1.5 = 66.5 meters.
To calculate the average velocity, we can divide the displacement by the time:
Average velocity = total displacement / total time
Average velocity = 66.5 meters / 4.85 seconds
Average velocity ≈ 13.71 m/s
Therefore, the magnitude of the average velocity of the rocket for the 4.85 seconds of its flight is approximately 13.71 m/s.