Write the balanced equations for the following examples:
a) potassium hydroxide + sodium sulfide --> potassium sulfide + sodium hydroxide
b) carbon disulfide + oxygen --> carbon dioxide + sulfur dioxide
The a reaction is nonsense but here is the equation. Just remember it won't work.
KOH + Na2S ==> K2S + NaOH
b)
CS2 +3O2 ==> CO2 + 2SO2
To write the balanced equations for the given examples, we need to make sure that the number of atoms of each element is the same on both sides of the equation. Here's how you can balance these equations step by step:
a) potassium hydroxide + sodium sulfide --> potassium sulfide + sodium hydroxide
To balance this equation, we first count the number of atoms on both sides:
On the left side:
1 potassium (K) atom
1 hydrogen (H) atom
1 oxygen (O) atom
1 sodium (Na) atom
1 sulfur (S) atom
On the right side:
1 potassium (K) atom
1 hydrogen (H) atom
1 oxygen (O) atom
1 sodium (Na) atom
1 sulfur (S) atom
The number of atoms for each element is already balanced. Therefore, the balanced equation is:
2 KOH + Na2S --> K2S + 2 NaOH
b) carbon disulfide + oxygen --> carbon dioxide + sulfur dioxide
On the left side:
1 carbon (C) atom
2 sulfur (S) atoms
2 oxygen (O) atoms
On the right side:
1 carbon (C) atom
2 sulfur (S) atoms
3 oxygen (O) atoms
To balance the oxygen atoms, we need to multiply the carbon dioxide product by 3, which will give us the following equation:
CS2 + 3 O2 --> CO2 + 2 SO2
Now the equation is balanced with respect to the number of atoms for each element.