Chemistry

3.0 moles each of carbon monoxide, hydrogen, and carbon are placed in a 2.0 liter vessel and allowed to come to equilibrium according to the equation: CO(g)+H2(g)-->C(s)+H20(g)
if the equilibrium constant at the temperature of the experiment is 4.0, what is the equilibrium concentration of water vapor?

asked by Kelly Hills
  1. 3.0 mols/2.0 L = 1.5M
    ..........CO + H2 ==> C + H2O
    initial..1.5..1.5....1.5...0
    change....-x...-x.....x....x
    equil...1.5-x..1.5-x..x....x

    Kc = 4.0 = (H2O)/(C0)(H2O)
    Substitute from the ICE chart into the Kc expression and solve for x.

    posted by DrBob222
  2. [H2O]=.81

    posted by Kassidy
  3. [H2O]=1M

    posted by Jenny
  4. H2O = 9M

    posted by Mohin

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