2NaOH+2Al+2H2O --> 2NaAlO2+3H2
here is the reaction. If i am trying to find the mass of hydrogen produced and i am trying to convert .95 moles Al to moles H, which number from the reaction do I use for H when converting from moles to moles? Do I 6 because that's the number that balances the Hydrogen, or is that wrong?
To convert from .95 mol Al to mol H, you would use the coefficients in the balanced equation.
Here's an example of a stoichiometry problem:
http://www.jiskha.com/science/chemistry/stoichiometry.html
To determine the number to use for hydrogen when converting moles of aluminum to moles of hydrogen, you need to consider the balanced equation for the reaction:
2NaOH + 2Al + 2H2O -> 2NaAlO2 + 3H2
From the equation, you can see that for every 2 moles of aluminum (Al) that react, 3 moles of hydrogen gas (H2) are produced. Therefore, the correct number to use for hydrogen (H2) when converting from moles of aluminum (Al) to moles of hydrogen gas (H2) is 3.
To find the mass of hydrogen produced, you need to convert moles of aluminum (Al) to moles of hydrogen (H2) using the balanced equation. In the balanced equation, the stoichiometric coefficient in front of each compound represents the mole ratio between reactants and products.
In the given reaction:
2NaOH + 2Al + 2H2O → 2NaAlO2 + 3H2
The coefficient in front of H2 (hydrogen gas) is 3. This means that for every 2 moles of aluminum (Al) reacting, 3 moles of hydrogen (H2) are produced.
If you have 0.95 moles of aluminum (Al), you can use the mole ratio to convert this to moles of hydrogen (H2):
0.95 moles Al x (3 moles H2 / 2 moles Al) = 1.425 moles H2
So, if you have 0.95 moles of aluminum (Al), it will react to produce 1.425 moles of hydrogen gas (H2).
Remember to always use the coefficients in the balanced equation to determine the mole ratio when converting between different substances.