The perimeter of rectangular playground is 200 feet. If the length is 5 feet less than twice the width, what are dimensions of the playground
Let's assume that the width of the rectangular playground is represented by "w" feet.
According to the given information, the length of the playground is 5 feet less than twice the width. Therefore, the length can be represented as 2w - 5.
The perimeter of a rectangle is given by the formula: 2(length + width). So, for our playground, the perimeter is 200 feet.
We can now set up an equation to solve for the dimensions:
2(length + width) = 200
Substituting the values for length and width:
2((2w - 5) + w) = 200
Simplifying the equation:
2(3w - 5) = 200
6w - 10 = 200
6w = 210
w = 35
So, the width of the playground is 35 feet.
Substituting the value of w into the equation for length:
length = 2w - 5 = 2(35) - 5 = 70 - 5 = 65
Therefore, the dimensions of the rectangular playground are 35 feet for the width and 65 feet for the length.
To find the dimensions of the playground, we can set up some equations based on the given information.
Let's assume the width of the playground is "x" feet.
According to the problem, the length is 5 feet less than twice the width. So, the length would be (2x - 5) feet.
The perimeter of a rectangle is calculated by adding the lengths of all its sides. In this case, the perimeter is given as 200 feet.
Perimeter = 2(Length + Width)
Substituting the values we have:
200 feet = 2((2x - 5) + x)
Now, we can solve this equation to find the value of x, which represents the width.
200 = 2(3x - 5)
200 = 6x - 10
6x = 210
x = 35
Therefore, the width of the playground is 35 feet.
To find the length, we substitute the value of x into the equation for the length:
Length = 2x - 5
Length = 2(35) - 5
Length = 70 - 5
Length = 65
Therefore, the dimensions of the playground are 35 feet by 65 feet.
P = 2L + 2W
200 = 2(2W - 5) + 2W
200 = 4W - 10 + 2W
200 + 10 = 6W
210 = 6W
35 = W