A 50.0mL volume of AgNO3, solution contains 0.0285 mol AgNO3 (SILVER NITRATE). What is the molarity of the solution?
Look at the definition.
M = moles/L soln
M = 0.0285 mols/0.050 L = ?
M = 0.0285 mols/0.050 L
M = 0.57 mols/L
thanks i now know the formular bt hey how would u define Molarity and in what part of living does it apply? Am trying to understand it.
To find the molarity (M) of a solution, we use the formula:
Molarity (M) = moles of solute / volume of solution in liters
Given:
Volume of AgNO3 solution = 50.0 mL = 0.0500 L
Moles of AgNO3 = 0.0285 mol
Using the formula, we can calculate the molarity of the solution as follows:
Molarity (M) = 0.0285 mol / 0.0500 L
Molarity (M) = 0.57 mol/L
Therefore, the molarity of the AgNO3 solution is 0.57 M.
To find the molarity of the solution, you need to divide the number of moles of solute (AgNO3) by the volume of the solution in liters.
Given:
Volume of solution (V) = 50.0 mL = 50.0/1000 = 0.050 L
Number of moles of AgNO3 (n) = 0.0285 mol
Molarity (M) = moles of solute / volume of solution in liters
Molarity (M) = n / V
Substituting the given values:
Molarity (M) = 0.0285 mol / 0.050 L
Calculating:
Molarity (M) = 0.570 M
Therefore, the molarity of the AgNO3 solution is 0.570 M.