in apool game,a cue ball traveling at 0.75 m/s hits the stationary eight ball The eight ball moves with a velocity of 0.25 m/s at an angle of 37 deg reletive to the cue balls inital direction assuming that the collision is inelastic at what angle will the que be deflected and what will be its speed?

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  1. Whether the collision is elastic or inelastic, the total momentum of the two balls in the direction perpendicular to the cue ball's initial direction must be zero, since there was no original momentum in that direction. Therefore
    MV1 sin 37 - MV2 sin A = 0
    In addition,
    M Vo = M cos 37 + M V2 cos A
    since momentum in the forward direction is conserved.
    The M's all cancel out
    Vo = 0.75 m/s
    V1 = 0.25 m/s is the eight-ball's final velocity.
    "A" is the unknown angle of the cue ball, and V2 is its velocity. It will be a negative angle.
    You have two equations in two unknowns to solve.

    We will be glad to critique your work.

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  2. The velocity is 0.0000 m/s

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  3. the answer is 0

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  4. its a glancing collision, i believe that the question improperly says the collision is inelastic. It should be elastic. there fore the sum the y and x vectors. substitute. You should get velocity .57 m/s and 15.2 degrees

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