Two forces are applied to a car in an effort to move it, as shown in the following figure, where F1 = 428 N and F2 = 358 N. (Assume up and to the right as positive directions.)
a) What is the resultant of these two forces? magnitude and direction
b) If the car has a mass of 3,000 kg, what acceleration does it have? Ignore friction.
i can't add the picture...
there is a car with F1 10 degrees to the left of the vertical axis and F2 30 degrees right of the vertical axis
Resultant=451.45N and direction is upwards
To find the resultant of the two forces in part a):
1. Draw a vector diagram for the two forces. Place F1 and F2 head-to-tail, with the tail of F1 starting at the beginning point of F2.
2. The resultant force, denoted as R, is the vector that connects the tail of F1 to the head of F2.
3. Measure the length of R (in millimeters or centimeters) using a ruler or measuring tool.
4. Multiply the measured length (in millimeters or centimeters) by a scale factor to convert it to newtons (N) based on the given scale (e.g., 1 cm = 100 N).
5. Use a protractor to measure the angle between the positive x-axis and the direction of R. Make sure to use the correct protractor orientation (360-degree or 180-degree). Note down the measured angle.
To calculate the acceleration of the car in part b):
1. Use Newton's second law, which states that the acceleration of an object is equal to the net force acting on it divided by its mass.
2. Calculate the net force by taking the sum of F1 and F2.
3. Divide the net force by the mass of the car to determine the acceleration.
4. Note that in this problem, friction is ignored.
Please provide the figure or specific values for F1 and F2, as well as the mass of the car to proceed with the calculations.