how many liters hydrogen if you react 3.51 L of .97M hydrochloric acid with excess zinc?

Zn + 2HCl ==> ZnCl2 + H2

mols HCl = M x L = ?
From the equation, mols H2 formed is 1/2 mols HCl.
I suppose you want the volume at STP. That will be mols H2 x 22.4L/mol = ?