chemistry

Calculate the standard free-energy change for the following reaction at 25 °C.
2Au^3+(aq) + 3Ni(s) -->2Au(s) + 3Ni^2+(aq)

  1. 👍
  2. 👎
  3. 👁
  1. Calculate Eo for the cell then substitute in dGo = -nFEo and solve for dGo.

    1. 👍
    2. 👎
  2. for n do you have to use the balanced number of before balancing? i would assume balance it first but i wanted to double check

    1. 👍
    2. 👎
  3. I've done this problem 4 times and keep getting it wrong. Could you please check my work?

    3e- + Au^3+ --> Au and E=1.52
    Ni--> Ni^2+ + 2e- and E = .26
    total E = 1.78

    dGo = -12(9.65x10^4)(1.78) = -2061240J or -2061.24kJ

    1. 👍
    2. 👎
  4. Thanks for showing your work.
    I think your problem is that you are using 12 for n but there are only 6 e involved. You multiplied Au half by 2 (to make 6) and multiplied Ni half by 3 (to make 6) so 6 goes in for n.

    1. 👍
    2. 👎
  5. you are little wrong. because 6 e- are gain and lose. Also, E for Au is 1.498 or not 1.50.

    So the correct answer is -1019.04kj/mol

    I used yours but got wrong and then, i tried again and got this answer correct.

    1. 👍
    2. 👎
  6. The answer should be
    (-6) (96.485 kj)(1.758)
    = -1017.72

    1. 👍
    2. 👎
  7. dGo = -nFEo

    where n = 6
    F = 96,485
    and Eo = cathode - anode = (+1.498) - (-0.26) = 1.758

    So,
    (-6)(96,485)(1.758) = -1,017,720 J or -1017.72 KJ

    (Make sure you divide by 1,000 to convert from J to KJ if the question asks for the answer in KJ)

    1. 👍
    2. 👎

Respond to this Question

First Name

Your Response

Similar Questions

  1. Chem

    For the reaction, 3C2H2(g) ===> C6H6 at 25°C, the standard enthalpy change is -631 kJ and the standard entropy change is -430 J/K, Calculate the standard free energy change (in kJ) at 25°C. What is the formula that relates

  2. Chemistry

    Calculate delta G of the reaction at 25 degrees C: 2Au^3+ (aq) + 3Ni(s) 2Au(s) + 3Ni^2+(aq) Au3+ + 3e- ==> Au Eo = +1.50V Ni2+ + 2e- ==> Ni Eo = -0.23 V 2Au3+ + 3Ni ==> 3Ni2+ + 2Au The answer is -1.00 x 10^3 kJ but i'm not getting

  3. Chemistry

    A solution of AuCl- is mixed with a solution of Sn2+ under standard conditions. What is the equation? the answer is 2AuCl4- + 3Sn2+ -> 3Sn4+ + 2Au + 8Cl- how do i get this? ITS desperate... plz help me! THANK_YOU SO MUCH!

  4. Chemistry

    The standard internal energy change for a reaction can be symbolized as ΔU°rxn or ΔE°rxn. For the following reaction equations, calculate the energy change of the reaction at 25 °C and 1.00 bar. Sn(s) + 2Cl2(g) --> SnCl4(l)

  1. Chemistry

    C2H2(g) + 2 H2(g)--> C2H6(g) Information about the substances involved in the reaction represented above is summarized in the following tables. Substance So (J/mol∙K) ∆Hºf (kJ/mol) C2H2(g) 200.9 226.7 H2(g) 130.7 0 C2H6(g) -

  2. Chemistry

    Calculate the standard entropy, ΔS°rxn, of the following reaction at 25.0 °C using the data in this table. The standard enthalpy of the reaction, ΔH°rxn, is –44.2 kJ·mol–1. C2H4(G)+H20 ---> C5H5OH ΔS°rxn= ______

  3. chemistry

    The standard internal energy change for a reaction can be symbolized as ΔU°rxn or ΔE°rxn. For the following reaction equations, calculate the energy change of the reaction at 25 °C and 1.00 bar. Sn(s) + 2Cl2(g) --> SnCl4(l)

  4. Chemistry

    Calculate the standard free-energy change for the following reaction at 25 C degrees. 2Au^3+(aq)+3Ni(s) 2Au(s)+3Ni^2+(aq) Ni2+(aq) + 2e- -> Ni(s) E=-0.26 Au3+(aq) + 3e- -> Au(s) E=+1.498 G= ? KJ Would it be G=1.758? •Chemistry -

  1. Chemistry

    For the reaction 2CO2(g) + 5H2(g)C2H2(g) + 4H2O(g) H° = 46.5 kJ and S° = -124.8 J/K The standard free energy change for the reaction of 1.75 moles of CO2(g) at 328 K, 1 atm would be ___ kJ This reaction is (reactant, product)

  2. Chemistry

    For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all species. For the reaction 2NO(g) + O2(g) --> 2NO2(g) the standard change in Gibbs free energy is ΔG° = -69.0 kJ/mol. What is ΔG for

  3. chemistry

    for the reaction 3C2H2=> C6H6 at 25 C, the standard enthalpy change is -631 KJ and the standard entropy change is -430 J/K. calculate the standard free energy change at 25 C. show all work!

  4. Chemistry

    C2H2(g) + 2 H2(g)--> C2H6(g) Information about the substances involved in the reaction represented above is summarized in the following tables. Substance/ So (J/mol∙K) /∆Hºf (kJ/mol) C2H2(g) / 200.9 / 226.7 H2(g)/ 130.7 / 0

You can view more similar questions or ask a new question.