# Algebra and Discrete Geometry

A large family wedding for the Smiths will require 113 trays of sandwiches, 116 trays of hors d' oeuvres, and 144 trays of sweets. Hands-Off caterers can make 15 trays of sandwiches, 10 trays of hors d'oeuvres, and 12 trays of sweets in one day. Hands-Free caterers can make 10 trays of sandwiches, 13 trays of hors d'oeuvres, and 14 trays of sweets in a day. Hand-Some caterers can make 12 trays of sandwiches, 15 trays of hors d'oeuvres, and 20 trays of sweets in a day. ****All three caterers are hired. How many days in advance of the wedding must each caterer begins their preperation of the food? Hint: 3 equations with 3 unknowns.

Btw, I know I need to create three equations and solve it using elimination. 1 for each caterer, x, y, and z.

oh and each will represent HOW MANY DAYS MUST EACH CATERING PARTY START TO PREPARE FOOD BEFORE THE WEDDING.

15x + 10y + 12z = 113
10x + 13y + 15z = 116
12x + 14y + 20z = 144

1. 👍 0
2. 👎 0
3. 👁 137

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