The largest tree in the world is the General Sherman sequoia in Sequoia National Park, California. It is 275 feet high, has a diameter of 36.5 feet, and has an estimated weight of 2,150 tons. Fin the sequoia's circumference to the nearest tenth of a foot. Use 3.14
C = pi * d
I don't understand the part of "nearest tenth of a foot". My answer is 114.61 but I don't get the part above mentioned.
Rounding it to the nearest tenth is 114.6
The first place after the decimal point is the tenths place.
Words
To find the circumference of a tree, you can use the formula:
Circumference = 2 * π * radius
In this case, the given information is the diameter of the tree, which is 36.5 feet. The radius is half of the diameter, so the radius would be 36.5/2 = 18.25 feet.
Before calculating the circumference, let's approximate π to 3.14, as mentioned in the question.
Now, we can substitute the known values into the formula:
Circumference = 2 * 3.14 * 18.25
Calculating this equation, we get:
Circumference = 2 * 3.14 * 18.25
= 114.74 feet (rounded to two decimal places)
Therefore, the approximate circumference of the General Sherman sequoia is approximately 114.7 feet.