At the beginning of the week, an electronics store took count of how many tvs and radios there were in the stockroom. The manager found that there was a ratio of 3 tvs for every 2 radios.
At the end of the week, the manager counted 24 boxes left in the stockroom. Using the original ratio, find the number of tvs & the number of radios that were left in the stockroom.
I forgot to mention there were 18 radios counted on Monday
I tried 3x + 2x = 24
5x = 4.8
then multiply 3 • 4.8 = 15.4 and 2 • 4.8 = 9.6
which means 14 tvs & 10 radios would be left
On monday, 3/2 = x/18 where x is numba of tv x=27...bt d problm here is dat no relationship in terms of hw many tv or radio ix containd in per box
To find the number of TVs and radios that were left in the stockroom at the end of the week, we can use the given ratio of TVs to radios.
Let's start by setting up a proportion using the ratio 3 TVs to 2 radios (3:2).
Since we know that there were 24 boxes left in the stockroom, and each box contains either a TV or a radio, we can set up the equation:
(3 TVs / 2 radios) = (x TVs / 24 boxes)
Cross-multiplying, we have:
3x = 2 * 24
Simplifying, we get:
3x = 48
Next, we can solve for x (the number of TVs):
x = 48 / 3
x = 16
Therefore, there were 16 TVs left in the stockroom at the end of the week.
To find the number of radios, we can substitute the value of x into the original ratio:
2 radios = (3 TVs / 2 radios) * x TVs
2 radios = (3/2) * 16
2 radios = 24
Therefore, there were 24 radios left in the stockroom at the end of the week.