57 Cds in 8 organizers drawpicturesto tell how many are in each group and how many are left over.
57 / 8 = ?
To solve this problem, let's represent the number of CDs in each group using a picture.
We have 57 CDs and 8 organizers. We want to distribute the CDs evenly among the organizers and determine how many are in each group and how many are left over.
Step 1: Divide the total number of CDs by the number of organizers to find the number of CDs in each group.
57 รท 8 = 7 with a remainder of 1.
Step 2: Draw pictures to represent the number of CDs in each group.
Let's draw 8 rectangles to represent the 8 organizers. In each rectangle, we will draw 7 circles to represent the number of CDs in each group.
| O O O O O O O |
| O |
| O |
| O |
| O |
| O |
| O |
| O |
Step 3: Determine how many CDs are left over.
We have a remainder of 1, which means there is one CD left over that cannot be evenly divided among the organizers.
So, in each group, there are 7 CDs, and there is 1 CD left over.
To visualize the distribution of the CDs into the organizers and determine how many are left over, we can draw a bar graph.
First, let's divide the 57 CDs into 8 equal groups as much as possible.
8 groups would have 57/8=7 CDs in each group (with some remainder).
To start drawing the bar graph, create 8 rectangular bars, each representing one organizer. Label the bars from 1 to 8.
Now, fill the first 7 bars with 7 CDs each.
For the remainder CDs, we have 57 modulo 8 = 1 CD left over.
Finally, draw an arrow from the first bar to indicate that it contains 7 CDs, and write the remainder (1 CD) as a separate number beside it.
In summary, the bar graph will display 7 CDs in each of the first 7 organizers, and the last organizer will have an arrow pointing to it, indicating that it contains 7 CDs, with an additional 1 CD written beside it to represent the remainder.
Organizer 1: |||||||
Organizer 2: |||||||
Organizer 3: |||||||
Organizer 4: |||||||
Organizer 5: |||||||
Organizer 6: |||||||
Organizer 7: |||||||
Organizer 8: ||||||| -> 1 CD