physics

A ball rolls with a speed of 6.4 m/s toward the edge of a table that is 0.7 m above the floor. The ball rolls off the table.

a. Find the magnitude of the balls velocity when it hits the floor. m/s

b. At what angle, measured from the horizontal, will the ball's velocity make with the ground? °

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asked by Tim
  1. The ball after leaving the table
    takes part in two motions: horizontal uniform motion
    L = v(hor) •t,
    and vertical free fall
    H = gt^2/2,
    t = sqroot(2H/g) = sqroot(2•0.7/9.8) = 1.43 s.
    v(vert) = gt = 9.8•1.43 = 14 m/s.
    tan α = v(vert)/ v(hor)=14/6.4=2.19
    α = 65.4 degr

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    posted by Elena
  2. SORRY!

    t = sqroot(2H/g) = sqroot(2•0.7/9.8) = 0.143 s.
    v(vert) = gt = 9.8•0.143 = 1.4 m/s.
    tan α = v(vert)/ v(hor)=1.4/6.4=0.219
    α = 12.35 degr

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    posted by Elena

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