You are pouring water from a cylindrical can is 7 cm in diameter and 10 cm high into a rectangular pan that is 20 cm in width, 9 cm in length and 14 cm deep. How many cans, can you pour into the pan? Use 22/7 for pi.
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Hi pepole
To find out how many cans of water can be poured into the rectangular pan, we need to calculate the volume of both the cylindrical can and the rectangular pan.
First, let's calculate the volume of the cylindrical can using the formula for the volume of a cylinder:
Volume of a cylinder = π * r^2 * h
Given diameter (d) = 7 cm, we can find the radius (r) by dividing the diameter by 2:
Radius (r) = d/2 = 7 cm / 2 = 3.5 cm
Height (h) of the cylindrical can is given as 10 cm.
Using the value of π as 22/7, we can calculate the volume of the can:
Volume of the can = (22/7) * (3.5 cm)^2 * 10 cm
= (22/7) * (12.25 cm^2) * 10 cm
= (22/7) * 122.5 cm^3
≈ 385 cm^3
Next, let's calculate the volume of the rectangular pan.
Volume of a rectangular pan = length * width * height
Given length = 9 cm, width = 20 cm, and depth = 14 cm, we can calculate the volume of the pan:
Volume of the pan = 9 cm * 20 cm * 14 cm
= 2520 cm^3
Finally, to determine the number of cans that can be poured into the pan, we divide the volume of the pan by the volume of a single can:
Number of cans = Volume of the pan / Volume of a can
= 2520 cm^3 / 385 cm^3
≈ 6.55
Since we cannot have a fraction of a can, the maximum number of cans that can be poured into the pan is 6.
Therefore, you can pour 6 cans of water into the pan.