What is the new pressure of 150ml of a gas that is compressed to 50ml, when the orginal pressure was 3.0atm?
(P1V1) = (P2V2)
9atm
To calculate the new pressure of a gas that is compressed, you can use Boyle's Law, which states that the product of the initial pressure and volume equals the product of the final pressure and volume.
Boyle's Law formula: P₁V₁ = P₂V₂
Given:
Initial pressure (P₁) = 3.0 atm
Initial volume (V₁) = 150 mL
Final volume (V₂) = 50 mL
First, convert the volumes to liters because the pressure should be in atm and the volume should be in liters for consistency.
Initial volume (V₁) = 150 mL = 150 mL ÷ 1000 mL/L = 0.150 L
Final volume (V₂) = 50 mL = 50 mL ÷ 1000 mL/L = 0.050 L
Now, we can substitute the values into the Boyle's Law equation:
P₁V₁ = P₂V₂
(3.0 atm)(0.150 L) = P₂(0.050 L)
Now, solve for P₂:
P₂ = (3.0 atm)(0.150 L) ÷ (0.050 L)
P₂ = 9.0 atm
Therefore, the new pressure of the gas, when compressed from 150 mL to 50 mL with an initial pressure of 3.0 atm, is 9.0 atm.