# chemistry

At a given temperature, you have a mixture of benzene (vapor pressure of pure benzene = 745 torr) and toluene (vapor pressure of pure toluene = 290 torr). The mole fraction of benzene in the vapor above the solution is 0.590. Assuming ideal behavior, calculate the mole fraction of toluene in the solution.
Answer

1. 👍 0
2. 👎 0
3. 👁 2,371
1. PA=XAP'A

1. 👍 0
2. 👎 0
2. 0.213

1. 👍 1
2. 👎 0
3. Since the benzene comes out better you will need more Toluene in the solution
to get its mol fraction above the solution
.59 = Pb/[(Pb)(Pt)}
Assumming 1 atm external pressure

.59 = (1-x)745/(1-x)745 + x(290)
=0.641

1. 👍 7
2. 👎 2

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