chemistry

At a given temperature, you have a mixture of benzene (vapor pressure of pure benzene = 745 torr) and toluene (vapor pressure of pure toluene = 290 torr). The mole fraction of benzene in the vapor above the solution is 0.590. Assuming ideal behavior, calculate the mole fraction of toluene in the solution.
Answer

  1. 👍 0
  2. 👎 0
  3. 👁 2,371
  1. PA=XAP'A

    1. 👍 0
    2. 👎 0
  2. 0.213

    1. 👍 1
    2. 👎 0
  3. Since the benzene comes out better you will need more Toluene in the solution
    to get its mol fraction above the solution
    .59 = Pb/[(Pb)(Pt)}
    Assumming 1 atm external pressure

    .59 = (1-x)745/(1-x)745 + x(290)
    =0.641

    1. 👍 7
    2. 👎 2

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