could you please help me....
Draw the graph of y=x-3 for values of x from -3 to 4
also how would you draw the graph of to 2x+y=7 for values of x from 0 to 5
i don't need the graph drawn i just need two plots for each!
thanks
can someone please help?
Of course! I can help you with that.
For the first question, you have the equation y = x - 3. To draw the graph, we need to plot a few points on the coordinate plane that satisfy this equation. Let's calculate the values of y for different values of x from -3 to 4.
When x = -3, y = (-3) - 3 = -6.
So the first point is (-3, -6).
When x = -2, y = (-2) - 3 = -5.
So the second point is (-2, -5).
Proceeding in the same manner, we find more points:
- When x = -1, y = (-1) - 3 = -4. Point: (-1, -4)
- When x = 0, y = (0) - 3 = -3. Point: (0, -3)
- When x = 1, y = (1) - 3 = -2. Point: (1, -2)
- When x = 2, y = (2) - 3 = -1. Point: (2, -1)
- When x = 3, y = (3) - 3 = 0. Point: (3, 0)
- When x = 4, y = (4) - 3 = 1. Point: (4, 1)
Now that we have several points, we can plot them on a graph and join them to form a line. The first plot will consist of the points we found.
For the second question, you have the equation 2x + y = 7. To draw the graph, we need to plot a few points on the coordinate plane again. This time, let's calculate the values of y for different values of x from 0 to 5.
When x = 0, y = 7 - (2 * 0) = 7.
So the first point is (0, 7).
When x = 1, y = 7 - (2 * 1) = 5.
So the second point is (1, 5).
Proceeding in the same manner, we find more points:
- When x = 2, y = 7 - (2 * 2) = 3. Point: (2, 3)
- When x = 3, y = 7 - (2 * 3) = 1. Point: (3, 1)
- When x = 4, y = 7 - (2 * 4) = -1. Point: (4, -1)
- When x = 5, y = 7 - (2 * 5) = -3. Point: (5, -3)
Again, we can plot these points on a graph and join them to form a line. The second plot will consist of the points we found.
I hope this helps! Let me know if you have any further questions.