A 1.04-L sample of gas at 759 mmHg pressure is expanded until its volumes is 2.24 L. What is the pressure in the expanded gas sample (at constant temperature)?

p1v1= p2v2

Great answer

To find the pressure in the expanded gas sample, we can use Boyle's Law, which states that the product of pressure and volume is a constant at constant temperature (P₁V₁ = P₂V₂).

In this case, we are given:
- Initial pressure (P₁) = 759 mmHg
- Initial volume (V₁) = 1.04 L
- Final volume (V₂) = 2.24 L

Let's substitute these values into Boyle's Law equation and find the pressure in the expanded gas sample (P₂):

P₁V₁ = P₂V₂

759 mmHg * 1.04 L = P₂ * 2.24 L

To solve for P₂, we can rearrange the equation:

P₂ = (P₁V₁) / V₂

Now, let's calculate the pressure:

P₂ = (759 mmHg * 1.04 L) / 2.24 L
P₂ = 784.84 mmHg

Therefore, the pressure in the expanded gas sample is approximately 784.84 mmHg.