# chemistry

Write the balanced chemical equation for each of these reactions. Include phases. When aqueous sodium hydroxide is added to a solution containing lead(II) nitrate, a solid precipitate forms. However, when additional aqueous hydroxide is added the precipitate redissolves forming a soluble [Pb(OH)4]2–(aq) complex ion.

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1. 2NaOH(aq) + Pb(NO3)2(aq) ==> Pb(OH)2(s) + 2NaNO3(aq)

Pb(OH)2(s) + 2NaOH(aq) ==> Na2Pb(OH)4(aq)

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2. I had the exact same question, but the when I tried the second equation, it was wrong.

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3. Same as Sarah

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4. second equation is

Pb(OH)2(s)+2OH^-(aq)<---> [Pb(OH)4]^2-(aq)

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5. You forgot the 2Na+(aq) ions as products of the second reaction.

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6. You have to put " Pb(OH)4(aq) " in square brackets... [Pb(OH)4]2–(aq)

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7. The answer for the second equation input is

Pb(OH)2 (s) + 2 NaOH^- (aq) --> [Pb(OH)4]^2- (aq) + 2 Na^+ (aq)

This part of the problem annoyed the hell out of me before I actually got it.

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8. Pb(OH)2 (s) + 2NaOH (aq) <--> [Pb(OH)4]^2- + 2Na^+ (aq)

Don't include the "-" in NaOH

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9. Ole ole Pumas!
The answer in right

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10. Na2Pb(OH)H(aq)

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11. 2NaOH(aq)+Pb(NO3)2(aq)--->Pb(OH)2(s)+2NaNO3(aq)

Pb(OH)2(s)+2OH^-(aq)--->[Pb(OH)4]^2-(aq)

just saw the answer on sapling.

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12. I can confirm Tamerra's answer.
2NaOH(aq)+Pb(NO3)2(aq)--->Pb(OH)2(s)+2NaNO3(aq)

Pb(OH)2(s)+2OH^-(aq)--->[Pb(OH)4]^2-(aq)

is the correct answer on Sapling.

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13. Not correct on sapling

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