How do you find log20, if log2=.301?? Please show work
log20 = log(10*2) = log10 + log2 = 1+log2 = 1.301
don't get it
To find log20 using log2 = 0.301, you can apply the logarithmic properties.
Step 1: Use the logarithmic property log(a*b) = log(a) + log(b) to rewrite log20 as a sum of logarithms of its prime factors.
log20 = log(2 * 10)
Step 2: Apply the property log(a^n) = n * log(a) to further simplify the expression.
log20 = log(2) + log(10)
Step 3: Use the fact that log2 = 0.301 and log10 = 1 to substitute these values into the expression.
log20 = 0.301 + 1
Step 4: Add the values to get the final answer.
log20 โ 1.301
Therefore, log20 is approximately 1.301.