Algebra

Write an equation of the line containing the given point and perpendicular to the given line. Express your answer in the form y=mx+b. (2,4) 3x+y=6 The equation of line is y=, and explain how you have gotten the answer.

asked by Kristi
  1. 1. First you need to find the slope of the original line you are given which is 3x + y = 6. The slope is -A/B so it is -3/1 or just -3, m = -3.

    2. The slope of a line perpendicular is the negative reciprocal so the slope of the line perpendicular to the given line is 1/3.

    3. Use point slope form with the given point to find the equation of the line first before simplifying it to y=mx+b.

    Point slope form is y - y1 = m(x-x1) now substitute the point

    y-4=1/3(x-2)

    4. Now distribute the 1/3: y-4=1/3x - 2/3
    Then add 4 to the other side, make 4 into 12/3 to give it a command denominator making it easier to add.

    y = 1/3x + 10/3.

    posted by Elle
  2. Thank You so much Elle

    posted by Kristi

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