# calculus

Hello. I need help finding the open intervals of this equation:
f(x)=3x^2-12
I already took the derivative of it by using the derivative test and I got 2,-2 as critical numbers

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1. The function is defined and continuous everywhere. I don't see how an "open interval" applies to it, but one can define a segment of the function in any open or closed interval one chooses.

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posted by drwls

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