One gram of nickel has 1.026 × 1022 atoms,
and each nickel atom has 28 electrons.
How many electrons are contained in 9.00 g
of nickel?
To find the number of electrons in 9.00 g of nickel, we will follow these steps:
Step 1: Calculate the molar mass of nickel.
Step 2: Convert the mass of nickel to moles.
Step 3: Use Avogadro's number to convert moles to the number of atoms.
Step 4: Multiply the number of atoms by the number of electrons per atom.
Let's start with step 1:
Step 1: Calculate the molar mass of nickel.
The molar mass of nickel (Ni) is approximately 58.6934 g/mol.
Moving on to step 2:
Step 2: Convert the mass of nickel to moles.
We have 9.00 g of nickel. To convert grams to moles, we divide by the molar mass:
Number of moles = mass (g) / molar mass (g/mol)
Number of moles of nickel = 9.00 g / 58.6934 g/mol ≈ 0.1534 mol
Now, moving on to step 3:
Step 3: Use Avogadro's number to convert moles to the number of atoms.
Avogadro's number (6.022 × 10^23 atoms/mol) tells us that there are 6.022 × 10^23 atoms in one mole of any substance.
Number of atoms of nickel = Number of moles × Avogadro's number
Number of atoms of nickel = 0.1534 mol × 6.022 × 10^23 atoms/mol ≈ 9.245 × 10^22 atoms
Finally, step 4:
Step 4: Multiply the number of atoms by the number of electrons per atom.
Each nickel atom has 28 electrons.
Number of electrons = Number of atoms × Number of electrons per atom
Number of electrons = 9.245 × 10^22 atoms × 28 electrons/atom
Number of electrons ≈ 2.588 × 10^24 electrons
Therefore, there are approximately 2.588 × 10^24 electrons in 9.00 g of nickel.