# Physics

A driver in a car traveling at a speed of 56.0 mi/h sees a deer 116 m away on the road. Calculate the minimum constant acceleration that is necessary for the car to stop without hitting the deer (assuming that the deer does not move in the meantime).

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1. V=56mi/h * 1600m/mi * 1h/3600s=24.9 m/s

a = (Vf^2-Vo^2)/2d,
a = (0-(24.9)^2) / 232 = -2.67 m/s^2.

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posted by Henry

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