A solution contains 1.53x10-3 M Ca(NO3)2, How many nitrate ions are there in 1.2x10-6 L (1.2 µL) of this solution?

moles Ca(NO3)2 = M x L = ?

moles NO3^- = 2x that.
Then 6.022E23 x M NO3^- to obtain the number of nitrate ions.