A cup of teat containing 400g of liquid at 20 degrees celsius was heated. If 58.5 kj of heat was absorbed by the tea, what would the final temperature be? Assume that the specific heat of the tea is the same as that of water (4.18).

I am not sure how to start this problem.

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  1. You know the specific heat formula of
    q = mass x specific heat x (Tfinal-Tinitial). Start there. Substitute and solve for Tf

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  2. so I did 4.18 = 400 X 58.5 X (Tf-30)
    4.18 =I amnot sure what to do on this side. Do I multiply 400, 58.5 and 30?

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  3. 4.18 is the specific heat (and it states that in the problem), not q.

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  4. I did 400/58.5 (4.18) and got 28.6 degrees celsius. Was I suppose to use the 20 degrees that was stated in the problem?

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