Please help me to solve these two equations step by step. They are quadratic equations
1).2x^2+9x+4=0
2).5x^2=-7x
write them so all the x variables are on one side
0 = -2x^2 + 9x - 4 and 0 = 6x^2 - x - 2
if you can, factor out any common factors (in this case, you can not for either equation)
You could use the quadratic formula or just a little trial and error to factor the equations.
The first one is easy to factor using trial and error
What factors of -2 and -4 would multiply then add up to 9? Factors for -2 are -2, 1, -1, 2 and factors for -4 are -4, 1, -2, 2, -1, 4
Plug any of those combinations in the formula x 0 = (?x+?)(?x+?)
In this case, 0 = (-2x+1)(x-4), then make each paretheses equal to 0 and solve for x (solution: x = 1/2 or 4)
Both equations would probably be more easily solved using the quadratic formula xoxo gothgirl- kk
hope that helps :D
Sure! I can help you solve these quadratic equations step by step.
1) 2x^2 + 9x + 4 = 0
To solve this equation, we can use the quadratic formula, which is given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this equation, a = 2, b = 9, and c = 4.
Substitute these values into the quadratic formula:
x = (-(9) ± √((9)^2 - 4(2)(4))) / (2(2))
x = (-9 ± √(81 - 32)) / 4
x = (-9 ± √49) / 4
x = (-9 ± 7) / 4
Now we have two possible solutions:
x1 = (-9 + 7) / 4 = -2/4 = -1/2
x2 = (-9 - 7) / 4 = -16/4 = -4
So the solutions to the equation 2x^2 + 9x + 4 = 0 are x = -1/2 and x = -4.
2) 5x^2 = -7x
To solve this equation, we can bring all the terms to one side of the equation to form a quadratic equation in standard form. In this case, we subtract -7x from both sides:
5x^2 + 7x = 0
Now, we need to factor out the common factor, which is x:
x(5x + 7) = 0
Applying the zero-product property, we know that the equation is true if either x = 0 or (5x + 7) = 0.
Solving for x:
1) x = 0
2) 5x + 7 = 0
5x = -7
x = -7/5
So the solutions to the equation 5x^2 = -7x are x = 0 and x = -7/5.