ʃ (e^x – 4e^-x/e^x) dx
need help...thnks
The integral of e^x is e^x
(4e^-x)/(e^x) = 4e^(-2x), and the integral of that is -2*e^-2x
Add the two terms for the answer, and tack on a +C constant:
ʃ (e^x – 4e^-x/e^x) dx =
e^x - 2e^(-2x) + C
need help...thnks
(4e^-x)/(e^x) = 4e^(-2x), and the integral of that is -2*e^-2x
Add the two terms for the answer, and tack on a +C constant:
ʃ (e^x – 4e^-x/e^x) dx =
e^x - 2e^(-2x) + C