An airplane starts from rest and moves forward with a constant acceleration of 5 m/s2 along a runaway 250 m long. How long does it take the plane to reach a speed of 46.0 m/s?
v = a t
5 t = 46
To find the time it takes for the airplane to reach a speed of 46.0 m/s, we can use the following kinematic equation:
v = u + at
Where:
v = final velocity (46.0 m/s)
u = initial velocity (0 m/s since the plane starts from rest)
a = acceleration (5 m/s²)
t = time
Rearranging the equation to solve for time (t), we get:
t = (v - u) / a
Substituting the given values into the equation, we have:
t = (46.0 m/s - 0 m/s) / 5 m/s²
t = 46.0 m/s / 5 m/s²
t = 9.2 s
Therefore, it will take the plane 9.2 seconds to reach a speed of 46.0 m/s.