# Math 11

I need help on this math problem.

The width of a certain painting is 5cm less than twice the length. The length of the diagonal distance across the painting is 107cm. Find the length and width. Round your answer to 2 decimal places.

Substitute:
diagonal distance: 107cm
length: L
width: 2L-5

Is the substitutes correct?
Should I use the pythagoras method?
Can someone put me in the right track please so I can work out the problem?

1. 👍
2. 👎
3. 👁
1. yes
yes

L^2 + (2L-5)^2 = 107^2
L^2 + 4L^2 - 20L + 25 = 11449
L = 49.84

1. 👍
2. 👎
2. the next step is:

5L^2-20L=11424

right?

1. 👍
2. 👎
3. Almost. Set the equation to zero to solve:

5L^2-20L-11424 = 0

then use the quadratic formula to get L.

1. 👍
2. 👎

## Similar Questions

1. ### maths

The width of a rectangular painting is 3inches more than twice the height .It is frames in a 2.5inches wide frames. what is the expression for the combined are of the painting and frame? Factorise the expression if it is

2. ### painting

28. Van Gogh’s painting Starry Night measures 92 cm long by 73 cm high. You buy a poster that shows an enlargement of the painting. The poster measures 120 cm long by 100 cm high. Is the poster an accurate representation of the

3. ### PRE-CALC

A large painting in the style of Rubens is 3 feet longer than it is wide. If the wooden frame is 12 in wide and the area of the picture frame is 208 ft^2, find the dimensions of the painting. So I know the width would be x and the

4. ### Math

Sally painted a picture that has an area of 480 square inches. The length of the painting is 1 1/5 its width. Which of the following could be the dimensions of Sally’s painting? A. 20 inches by 24 inches B. 12 inches by 40

1. ### algebra

A small painting has an area of 400 c m 2 . The length is 4 more than 2 times the width. Find the dimensions of the painting. Solve by completing the square. Round answers to the nearest tenth of a centimeter.

2. ### Algebra

A painting is 18 inches wide. It is placed inside a frame with a border that is x inches wide. The total width of the painting and the frame is 24 inches. Create an equation to model the situation, and then solve the equation to

3. ### algebra

The perimeter of a rectangular painting is 354 centimeters. If the width of the painting is 79 centimeters, what is its length?

4. ### math help plzzz

the perimeter of a rectangle is 3.5 times the legth. the width is 2.5cm less than the legth. what is the width?

1. ### Algebra 1

Solve by completing the square: A rectangular patio has a length of (x + 6) m, a width of (x + 8) m, and a total area of 400 m2. Find the dimensions to the nearest tenth. Please help me with this math problem. Thanks so much.

2. ### math

the width of a math textbook is 0.75 inches. how many math textbooks can be placed standing up on a shelf that is 18 inches wide

3. ### Math

A square mirror has sides measuring 2 ft. less than the sides of a square painting. If the difference between their areas is 32 ft^2, find the lengths of the sides of the mirror and the painting? Square mirror= x-2 Painting=x I

4. ### math

a painting is 3 inches longer than it is wide. it is set in a rectangular border that is 2 inches wider than the painting on each side. if the area of the border is 100in^2 what are the dimensions of the painting? Here is a