A child bounces a 49 g superball on the side- walk. The velocity change of the superball is from 27 m/s downward to 12 m/s upward.
If the contact time with the sidewalk is 1 800
s, what is the magnitude of the average force exerted on the superball by the sidewalk?
Answer in units of N
To find the magnitude of the average force exerted on the superball by the sidewalk, we can use the equation:
Force = (mass * change in velocity) / time
First, let's find the change in velocity. The initial velocity is 27 m/s downward, and the final velocity is 12 m/s upward. To get the change in velocity, we need to subtract the initial velocity from the final velocity:
Change in velocity = final velocity - initial velocity
Change in velocity = 12 m/s - (-27 m/s)
Change in velocity = 12 m/s + 27 m/s
Change in velocity = 39 m/s
Now, let's substitute the values into the equation:
Force = (mass * change in velocity) / time
Force = (0.049 kg * 39 m/s) / 1.8 s
Calculating this:
Force = (1.911 kg*m/s) / 1.8 s
Force ≈ 1.06 N
Therefore, the magnitude of the average force exerted on the superball by the sidewalk is approximately 1.06 N.