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A skier of mass 54.6 kg comes down a slope of constant angle 21◦ with the horizontal.
The acceleration of gravity is 9.8 m/s2 .
What is the force on the skier parallel to the slope?
Answer in units of N

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Connor

  1. Ws = mg = 54.6 * 9.8 N./kg = 535.1 N. = Weight of skier.

    Fs = 535.1 N. @ 21 Deg. = Force of skier.
    Fp = 535.1*sin21 = Force parallel to the slope.

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    Henry

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