A football punter accelerates a 0.35 kg football from rest to a speed of 12.0 m/s in 0.30 s. What constant force does the punter exert on the ball?
F=ma=m(v2-v1)/t=0.35(12-0)/0.30=14 N
Thanks
To find the constant force exerted by the punter on the ball, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.
Based on the given information:
Mass of the football (m) = 0.35 kg
Final velocity of the football (v) = 12.0 m/s
Time taken (t) = 0.30 s
First, we need to find the acceleration of the football using the following equation:
acceleration (a) = (final velocity - initial velocity) / time
The initial velocity of the football is 0 because it starts from rest, so we have:
a = (12.0 m/s - 0 m/s) / 0.30 s
a = 40 m/s^2
Now we can calculate the force using Newton's second law:
force (F) = mass (m) * acceleration (a)
F = 0.35 kg * 40 m/s^2
F = 14 N
Therefore, the punter exerts a constant force of 14 Newtons on the ball.