# math-calculus

4x+3/2x-1-2 = 6x+2/2x-1

(4x+3)(-2) = (6x+2)
-8x-6 = 6x+2
-14x-6 = 2
-14x = 8
x = 4/-7

i not think i did this right.

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1. do you mean

[ (4x+3)/(2x-1) ] - 2 = (6x+2)/(2x-1)

??????
If so please use parentheses so I can tell numerator from denominator.
If my guess is correct:
(4x+3) -2 (2x-1) = 6x+2

4x + 3 -4x + 2 = 6 x + 2
3 = 6 x
x = 1/2

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2. sorry yes you are right but don't all 2x-1's cancel?

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3. i think it supposed to be this
(4x+3)(-2) = (6x+2)

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4. [ (4x+3)/(2x-1) ] - 2 = (6x+2)/(2x-1)

Multiply everything, all terms both sides including -2, by (2x-1)

[(4x+3)/(2x-1)](2x-1)-2(2x-1) = [(6x+2)/(2x-1) ] (2x-1)

You have to multiply that -2 by (2x-1) so the (2x-1) does not go away from the numerator when you clear it from the denominators.

so
(4x+3) -2 (2x-1) = 6x + 2

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[(4x+3)/(2x-1)](-2) = (6x+2)/(2x-1)

if so then

-2(4x+3) = 6x+2

-8x - 6 = 6x + 2

-14 x = 8

x = -4/7

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6. thank you but in back of book it say no solution so i very confused.

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7. If my solution of x = 1/2 is correct (and I think it is'
Then indeed the answer is NO SOLUTION
because
2x-1 = 0 if x = 1/2

division by 0

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8. I did not notice that, should have.

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9. thank you so much i not notice that either. thanks :)

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