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An HNO3 solution has a pH of 3.04. What volume of 0.015 M LiOH will be required to titrate 89.0 mL of the HNO3 solution to reach the equivalence point?

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Anonymous

  1. HNO3 + LiOH ==> LiNO3 + H2O

    The rxn is 1:1; therefore, we may use
    mLHNO3 x MHNO3 = mLLiOH x MLiOH
    Convert pH of 3.04 to H^+ by pH = -log(H^+) first, substitute, then solve for mL LiOH.

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    DrBob222

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