# Trig

If the center of a circle is at
(2,2) with a radius of 4 the equation of the graph would be :
a) (x-2)^2 + (y-2)^2 = 16
b) (x+2)^2 + (y+2)^2 = 16
I think it would be b
is that correct?

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1. I would put my money on a)

for centre (h,k) and radius r, the equation of the circle is
(x-h)^2 + (y-k)^2 = r^2

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