Ask questions and get helpful responses.

Calculus

For the function ƒ(x) = x2 find the slope of secants from the point (2, 4) to each of the following points.
(3, __ )
(2.5 , __ )
(2.1 , __ )
(2.01, __ )
(2.001, __ )
Using the pattern from question 1, what do you think the slope of a tangent at the point (2, 4) would be? Explain you answer.

  1. 👍
  2. 👎
  3. 👁
  4. ℹ️
  5. 🚩
  1. I will do the third point for you

    x = 2.1 so f(2.1) = (2.1)^2 = 4.41
    so slope of line between (2,4) and (2.1,4.41) is (4.41-4)/(2.1-2)
    = 4.1

    Now you do the rest in the same way.
    Do you notice what is happening?

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩

Respond to this Question

First Name

Your Response

Still need help? You can ask a new question.