the length of a rectangle is 6times as long as its breadth.

a.) what fraction of the perimeter of the rectangle is the length of the rectangle?
b.) find the ratio of the length of the rectangle to its breadth and to its perimeter.
c.) if the perimeter of the rectangle is 342.44cm, find the length and breadth of the rectangle.

the area of a rectangle field is 80m.if the ratio of the length to the breadth is 5 : 3,find its area.

the perimeter of a rectangle is 36cm if it is 12cm long find its width

To solve this problem, we'll need to use some basic concepts of geometry and algebra.

Let's call the length of the rectangle L and the breadth B.

a.) To find the fraction of the perimeter that the length of the rectangle represents, we need to find the perimeter of the rectangle. The perimeter of a rectangle is given by the formula: P = 2(L + B).

Since the length of the rectangle is 6 times as long as its breadth, we can write L = 6B.

Substituting this value into the perimeter formula, we get: P = 2(6B + B) = 14B.

The fraction of the perimeter represented by the length is given by: L / P = (6B) / (14B) = 6/14 = 3/7.

Therefore, the fraction of the perimeter of the rectangle that the length represents is 3/7.

b.) To find the ratio of the length of the rectangle to its breadth and to its perimeter, we divide the length by the breadth and the length by the perimeter.

Ratio of length to breadth: L / B = (6B) / B = 6.

Ratio of length to perimeter: L / P = (6B) / (14B) = 6 / 14 = 3 / 7.

So, the ratio of the length of the rectangle to its breadth is 6:1, and the ratio of the length to its perimeter is 3:7.

c.) To find the length and breadth of the rectangle when the perimeter is 342.44 cm, we can use the perimeter formula: P = 2(L + B).

Substituting the given perimeter value, we get: 342.44 = 2(L + B).

We also know that L = 6B. Substituting this value into the equation, we have: 342.44 = 2(6B + B) = 14B.

Simplifying the equation, we get: 342.44 = 14B.

Dividing both sides by 14, we find: B = 24.46 cm.

Substituting this value back into the equation L = 6B, we have: L = 6(24.46) = 146.76 cm.

Therefore, the length of the rectangle is 146.76 cm and the breadth is 24.46 cm.

45

if L = 6W, then

P = 2L+2W = 12W+2W = 14W

a) 6W/14W = 3/7
b) L:W = 6W:W = 6:1
see a) for L:P
c) 14W = 342.44
W = 24.46
L = 146.76